next up previous
Next: About this document ...

Quiz 4 - The Definition of the Derivative



(a) What is the derivative of f(x) at the point c? That is, give the

definition of the derivative.





\begin{displaymath}\lim_{h \to 0} \frac{f(c+h)-f(c)}{h}\end{displaymath}

OR


\begin{displaymath}\lim_{x \to c} \frac{f(x)-f(c)}{x-c}\end{displaymath}




(b) Use the definition of the derivative to find f'(x) for the following functions:

(1) f(x)=x+7




\begin{displaymath}\lim_{h \to 0} \frac{f(x+h)-f(x)}{h}\end{displaymath}


\begin{displaymath}=\lim_{h \to 0} \frac{(x+h)+7 -(x+7)}{h}=
\lim_{h \to 0} \frac{h}{h} = 1\end{displaymath}



(2) $f(x)=\frac{3}{x}$




\begin{displaymath}\lim_{h \to 0} \frac{f(x+h)-f(x)}{h}\end{displaymath}


\begin{displaymath}=\lim_{h \to 0} \frac{\frac{3}{x+h}-\frac{3}{x}}{h}
=\lim_{h \to 0} \frac{\frac{3x}{(x)(x+h)}-\frac{3(x+h)}{(x)(x+h)}}{h}\end{displaymath}


\begin{displaymath}=\lim_{h \to 0} \frac{3x-3x-3h}{(x)(x+h)h}=
\lim_{h \to 0} \frac{-3h}{(x)(x+h)h}\end{displaymath}


\begin{displaymath}=\lim_{h \to 0} \frac{-3}{x(x+h)} = \frac{-3}{x^2}\end{displaymath}



(3) $f(x)= \cos x$




\begin{displaymath}\lim_{h \to 0} \frac{f(x+h)-f(x)}{h}\end{displaymath}


\begin{displaymath}=\lim_{h \to 0} \frac{\cos (x+h) - \cos x}{h}\end{displaymath}


\begin{displaymath}=\lim_{h \to 0} \frac{ [\cos x \cos h - \sin x \sin h]-\cos x}{h}\end{displaymath}


\begin{displaymath}= \lim_{h \to 0} \frac{\cos x \cos h -\cos x -\sin x \sin h }{h}\end{displaymath}


\begin{displaymath}=\lim_{h \to 0} \frac{\cos x (\cos h - 1)}{h} +
\lim_{h \to 0} \frac{-\sin x \sin h }{h}\end{displaymath}


\begin{displaymath}= \cos x (0) -\sin x (1) = - \sin x\end{displaymath}



 


1999-10-07